i really dont know how to figure this out i would actually like help rather than just the answer so i can figure it out on my own Raythia and her friend, Mary, are going to a community cookout. At the cookout community members can hae a meal using any combination of 9 sides and 4 different main dishes, as shown on the menu below. Main Dishes----------------Sides Burger--------------------------salad hot dog---------------------cole slaw chicken-------------------------beans grilled veggies------------fruit salad -----------------------------corn on the cob ----------------------------mac and cheese ------------------------------potato salad --------------------------------biscui鈥?br> -------------------------------waterme鈥?br> Raythia wants a meal with 3 different sides with her grilled veggies. How many different combinations for Raythia's meal are possible? Mary wants a meal with 2 different sides with any type of main dish. How many different meal combinations are possible for Mary?|||All based on multiplication principle and combinations: Raythia wants a meal with 3 different sides with her grilled veggies. How many different combinations for Raythia's meal are possible? count of {grilled veggies, side1, side2, side4} = 1鈥(9,3) = 9鈥?鈥?/3鈥?鈥? = 1鈥?鈥?鈥? = 84 Note: we use combinations because the order in which the items are chosen is irrelevant. Mary wants a meal with 2 different sides with any type of main dish. How many different meal combinations are possible for Mary? count of {any main, side1, side2} = C(4.1)鈥(9,2) = 4鈥?鈥?/2鈥? = 4鈥?鈥? = 144|||Combination formula: nCr = n! / r! (n-r)! "n" is the total choices; the number of items. "C" is the combination term "r" is the items chosen. Raythia has 1 main dish choice with 3 sides chosen. The 1 is predetermined; so work out the sides. 9C3 = 9! / 3!(9-3)! ....becomes 9! / 3! (6)!...expand ! 9鈥?鈥?鈥?鈥?鈥?鈥?鈥?鈥?/3鈥?鈥?(6鈥?鈥?鈥?鈥?鈥?) now cancel out similiar values top and bottom 6,5,4,3,2,1 cancel top and bottom.... now solve what is left of the problem. 9鈥?鈥?/3鈥?鈥? = now you solve. -------------------------------------- Mary is a nCr +nCr of 1 main with 2 sides. Main dish: 4C1 + 9C2 [4! / 1!(4-1)!] + [9! / 2!(9-2)!] there is the formula set up. Here is a site to help you. http://www.mathwarehouse.com/probability鈥?/a>

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